Ledda/rpi-sensors
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finding a bug

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This commit is contained in:
Daniel Ledda
2020-10-31 16:23:25 +01:00
parent af9fe5152c
commit 7e86f0e5cf
1 changed files with 4 additions and 4 deletions
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8
main.go
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@@ -59,7 +59,7 @@ func readDataFromDHT(pin *gpio.Pin) ([5]byte, error) {
pin.PullUp() pin.PullUp()
pin.Input() pin.Input()
time.Sleep(30 * time.Microsecond) time.Sleep(30 * time.Microsecond)
// Wait for high low signal // Wait for low high signal
cyclesLo := cyclesForReading(pin, gpio.Low) cyclesLo := cyclesForReading(pin, gpio.Low)
if cyclesLo == Timeout { if cyclesLo == Timeout {
return [5]byte{}, errors.New(fmt.Sprintf(TimeoutErrInitial, "low")) return [5]byte{}, errors.New(fmt.Sprintf(TimeoutErrInitial, "low"))
@@ -102,9 +102,9 @@ func storeCycleCountsAsBinarySequence(cycles *[80]int) ([5]byte, error) {
for i := 0; i < 40; i++ { for i := 0; i < 40; i++ {
lowCycles := cycles[2 * i] lowCycles := cycles[2 * i]
highCycles := cycles[2 * i + 1] highCycles := cycles[2 * i + 1]
if (lowCycles == Timeout) || (highCycles == Timeout) { //if (lowCycles == Timeout) || (highCycles == Timeout) {
return [5]byte{}, errors.New("timed out waiting for sensor pulse") // return [5]byte{}, errors.New("timed out waiting for sensor pulse")
} //}
data[i / 8] <<= 1 data[i / 8] <<= 1
if highCycles > lowCycles { if highCycles > lowCycles {
data[i / 8] |= 1 data[i / 8] |= 1